Let's find out what is the probability of our subject to be in a
certain stress state
. We will use her transitional probability matrix#3480#> shown in
table 3.3. What is the initial probability
vector? Let's pretend we do not know in what state she is now. The
initial probability vector is then given by the "static" probability
distribution (table 3.4).
What is then the probability to find the subject in a given stress
state three time period ahead we observed her? We simply multiply the
initial probability vector with the transitional probability matrix#3481#> multiplied by itself three
time (third power); If we compute the transitional probability matrix#3482#> at a certain power
,
it yields the probabilities for transiting from state
to state
to
times ahead. For a power of three, the transitional probability matrix#3483#> is given in
table 3.5:
So the probabilities to find the subject in a given state without knowing in what state she is now is (cf. table 3.6). The probabilities to find her in a given state are the same as with the initial probability vector! It is not necessary so, but it happens when transitions converge rapidly to their long-term behavior.
Strangely enough the transitional probabilities in
table 3.5 are almost identical for each column.
Why is it so? If we let the transitional probability matrix#3484#> at a constantly greater power, the
resulting matrix converges to its long-term behavior (the
limit matrix
, denoted by letter
). That is, if we let this person
experience stress following a dynamics given by her transitional
probabilities, the best guess about the state she is would be this
limit matrix. In our example the limit matrix is
(table 3.7).
The result implies that if we observe her for a large number of days we can expect her to feel 13% of very low stress, 33% of low stress, 32% of moderate stress, 13% of medium stress, 5% of high stress and 3% of very high stress.
Since each row of the limit matrix
converges to identical
probabilities, it may be represented by a vector
. It may be
algebraically computed by solving the equation:
.